Let there be a circle centered on the origin. Let P be a point on the circle and O be the origin. Let the intersections of the tangent at P with the x and y axes be M and N. Let a line passing M and perpendicular to x-axis be m. Similarly a line n for N and y-axis. The trace of the intersection of m and n is the Cross Curve, as P moves on the circle.

Start with a circle centered on the origin with radius one
{Cos[t],Sin[t]}. Take its tangent vector, then find its tangent
equation, then find their intersections with the x and y axes, we
easily derive the parametric formula {Sec[t],Csc[t]}. To get the
Cartesian equation, we try the art of eliminating a variable. With
luck, we use formula Sin[t]^2+Cos[t]^2==1 and fairly easily derive the
Cartesian equation x^2+y^2==x^2*y^2.

Note that in deriving the Cartesian equation from the parametric, we have squared both sides of x==Sec[t] and y=Csc[t]. That means, we may obtain extraneous solution when x==0 or y==0, which is the case here. The Cartesian equation x^2+y^2-x^2*y^2==0 has a isolated point {0,0}.